document.write( "Question 67471: I am having a hard time understanding constants. Here is my problem: Determine the constant k so that the graph of 3x+(k-1)y=k+1 will have slope 5.\r
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Algebra.Com's Answer #48003 by ankor@dixie-net.com(22740)\"\" \"About 
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I am having a hard time understanding constants. Here is my problem: Determine the constant k so that the graph of 3x+(k-1)y=k+1 will have slope 5.
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\n" ); document.write( "Arrange the equation in the point/intercept form, y = mx + b
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\n" ); document.write( "(k-1)y = -3x + (k+1)
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\n" ); document.write( "The problem wants the slope (m) to = 5. This can be accomplished by dividing the
\n" ); document.write( "coefficient of x, (-3) by the coefficient of y,(k-1)
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\n" ); document.write( "Find the value of k which will give us a slope of 5:
\n" ); document.write( "5 = -3/(k-1)
\n" ); document.write( "5(k-1) = -3
\n" ); document.write( "5k - 5 = -3
\n" ); document.write( "5k = -3 + 4
\n" ); document.write( "5k = +2
\n" ); document.write( "k = 2/5
\n" ); document.write( "k = +.4
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\n" ); document.write( "Substitute .4 for k:
\n" ); document.write( "(.4-1)y = -3x + (.4+1)
\n" ); document.write( "-.6y = -3x + 1.4
\n" ); document.write( "y = (-3/-.6)x + (1.4/-.6)
\n" ); document.write( "y = +5x - 2.33
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\n" ); document.write( "The graph:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-4%2C+4%2C+-10%2C+10%2C+5x+-+2.33%29+\"
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\n" ); document.write( "Note that it has a slope of +5
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\n" ); document.write( "Did this make sense to you?
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