document.write( "Question 792404: To travel 88 miles, it takes Sue, riding a moped, 4 hours less time than it takes Doreen to travel 56 miles riding a bicycle. Sue travels 15 miles per hour faster than Doreen. Find the times and rates of both girls. \n" ); document.write( "
Algebra.Com's Answer #479970 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! To travel 88 miles, it takes Sue, riding a moped, 4 hours less time than it takes Doreen to travel 56 miles riding a bicycle. Sue travels 15 miles per hour faster than Doreen. Find the times and rates of both girls. \n" ); document.write( "---------------------- \n" ); document.write( "Sue DATA: \n" ); document.write( "distance = 88 miles; x-4 hrs ; rate = 88/(x-4) hours \n" ); document.write( "------------------------- \n" ); document.write( "Doreen DATA: \n" ); document.write( "distance = 56 miles; x hrs ; rate = 56/x hours \n" ); document.write( "------------------- \n" ); document.write( "Equation: \n" ); document.write( "88/(x-4) - 56/x = 15 mph \n" ); document.write( "--------- \n" ); document.write( "88x - 56(x-4) = 15x(x-4) \n" ); document.write( "--------- \n" ); document.write( "88x - 56x + 56*4 = 15x^2 - 60x \n" ); document.write( "--------- \n" ); document.write( "32x + 224 = 15x^2-60x \n" ); document.write( "------- \n" ); document.write( "15x^2 - 92x - 224 = 0 \n" ); document.write( "x = 8 hours \n" ); document.write( "==== \n" ); document.write( "Etc. \n" ); document.write( "Cheers, \n" ); document.write( "Stan . \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |