document.write( "Question 792404: To travel 88 miles, it takes Sue, riding a moped, 4 hours less time than it takes Doreen to travel 56 miles riding a bicycle. Sue travels 15 miles per hour faster than Doreen. Find the times and rates of both girls. \n" ); document.write( "
Algebra.Com's Answer #479970 by stanbon(75887)\"\" \"About 
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To travel 88 miles, it takes Sue, riding a moped, 4 hours less time than it takes Doreen to travel 56 miles riding a bicycle. Sue travels 15 miles per hour faster than Doreen. Find the times and rates of both girls.
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\n" ); document.write( "Sue DATA:
\n" ); document.write( "distance = 88 miles; x-4 hrs ; rate = 88/(x-4) hours
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\n" ); document.write( "Doreen DATA:
\n" ); document.write( "distance = 56 miles; x hrs ; rate = 56/x hours
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\n" ); document.write( "Equation:
\n" ); document.write( "88/(x-4) - 56/x = 15 mph
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\n" ); document.write( "88x - 56(x-4) = 15x(x-4)
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\n" ); document.write( "88x - 56x + 56*4 = 15x^2 - 60x
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\n" ); document.write( "32x + 224 = 15x^2-60x
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\n" ); document.write( "15x^2 - 92x - 224 = 0
\n" ); document.write( "x = 8 hours
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\n" ); document.write( "Etc.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan .
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