document.write( "Question 67468This question is from textbook Prentice Hall Algebra 1
\n" ); document.write( ": how do you graph x+3y=6 \n" ); document.write( "
Algebra.Com's Answer #47996 by vero(2)\"\" \"About 
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first, you need to change it into slope-intercept form.(y=mx+b) m=slope b=y intercept.\r
\n" ); document.write( "\n" ); document.write( "so when changing x+3y=6, you have to subtract x, from that side and you get 3y=-x+6, now you have to divide 3 to get y alone. so you get y=-x/3=6/3
\n" ); document.write( "and that turns out to be y=-x/3=2.
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\n" ); document.write( "\n" ); document.write( " change into slope intercept form
\n" ); document.write( "x+3y=6 --------------------------------> y=mx+b
\n" ); document.write( "y=mx+b
\n" ); document.write( "3y=-x=6
\n" ); document.write( "y=-x/3+2 m=slope which makes m=-1/3 rise/run.
\n" ); document.write( " b=y intercept which makes it b=2 which is (0,2)
\n" ); document.write( "so to graph this you have to go from (0,2)to down one to the right 3 which would be the second point (3,1) and the third point would be (0,6.
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