document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=792400>Question 792400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photographer wants to mix 3 liters of a 4% acetic acid solution with a 15% solution to get a 9% solution. how many liters of 15% solution should be used to obtain the 9% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479956 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A photographer wants to mix 3 liters of a 4% acetic acid solution with a 15% solution to get a 9% solution. how many liters of 15% solution should be used to obtain the 9% solution?<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.04*3 + 0.15x = 0.09(3+x)<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "4*3 + 15x = 9*3 +  9x<BR>\n" );
document.write( "6x = 5*3<BR>\n" );
document.write( "x = (1/2)5 = 2.5 liters (amt. of 15% solution needed)<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );