document.write( "Question 67446: A 12 foot ladder leans against the side of a building, making an angle of 30 degrees with the ground. To increase the reach of the ladder against the building, the ladder is moved so that it makes an angle of 60 degrees with the ground. To the nearest tenth of a foot, how much further up the building does the ladder now reach? \n" ); document.write( "
Algebra.Com's Answer #47994 by Earlsdon(6294)\"\" \"About 
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Let h1 be the height of the first reach.
\n" ); document.write( "\"sin%2830%29+=+h1%2F12\" Solve for h1.
\n" ); document.write( "\"h1+=+12sin%2830%29\"
\n" ); document.write( "\"h1+=+12%280.5%29\"
\n" ); document.write( "\"h1+=+6\"ft.\r
\n" ); document.write( "\n" ); document.write( "Let h2 be the new height.
\n" ); document.write( "\"sin%2860%29+=+h2%2F12\" Solve for h2.
\n" ); document.write( "\"h2+=+12sin%2860%29\"
\n" ); document.write( "\"h2+=+12%280.866%29\"
\n" ); document.write( "\"h2+=+10.39\"
\n" ); document.write( "The additional reach = h2-h2
\n" ); document.write( "\"h2-h1+=+10.39-6\"
\n" ); document.write( "Additional reach = 4.4 ft. (To the nearest tenth)
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