document.write( "Question 67445: From each of the the 4 corners of a rectangular piece of cardboard 8 inches wide, and 12 inches long, a 2 inch square is cut off.\r
\n" ); document.write( "\n" ); document.write( "A) What is the area of the new figure?\r
\n" ); document.write( "\n" ); document.write( "B) If the 4 sides of the new figure are folded straight up to form a box that is open at the top, what is the volume of this box?
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Algebra.Com's Answer #47993 by Earlsdon(6294)\"\" \"About 
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A. Find the area of the original piece of cardboard: A = 8X12 = 96 sq.in.
\n" ); document.write( "Subtract the area of the 4 removed corners: 4(2X2) = 16 sq.in.\r
\n" ); document.write( "\n" ); document.write( "A. New area = (8X12) - 4(2X2) = 96 - 16 = 80 sq.in.\r
\n" ); document.write( "\n" ); document.write( "The volume of the newly-formed box is found by multiplying the old length less two of the corners: (12-2(2) = 12-4 = 8 in.) by the old width less two of the corners: (8-2(2) = 8-4 = 4) by the height of the box (2 in.)
\n" ); document.write( "B. V = (12-4)(8-4)(2) = 8X4X2 = 64 cu.in.
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