document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=792256>Question 792256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ONE ANGLE OF A TRIANGLE IS THREE TIMES AS LARGE AS ANOTHER.THE MEASURE OF THE THIRD ANGLE IS 40 DEGREES MORE THAN THAT OF THE SMALLEST ANGLE FIND THE MEASURE OF EACH ANGLE. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479890 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle 1 = x<BR>\n" );
document.write( "angle 2 = 3x<BR>\n" );
document.write( "angle 3 = x + 40\r<BR>\n" );
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document.write( "angles 1 + 2 + 3 = 180<BR>\n" );
document.write( "x + 3x + (x + 40) = 180<BR>\n" );
document.write( "5x + 40 = 180<BR>\n" );
document.write( "5x + 40 -40 = 180 - 40<BR>\n" );
document.write( "5x = 140<BR>\n" );
document.write( "5x/5 = 140/5<BR>\n" );
document.write( "x = 28\r<BR>\n" );
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document.write( "check:<BR>\n" );
document.write( "28 + 3(28) + (28 + 40) = 180<BR>\n" );
document.write( "28 + 84 + 68 = 180<BR>\n" );
document.write( "180 = 180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );