document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=792084>Question 792084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lengths of the sides of a triangle are x+3,4x+1, and 5x. If its perimeter is 64, find the length of its sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479856 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x + 3) + (4x + 1) + 5x = 64<BR>\n" );
document.write( "x + 4x + 5x + 3 + 1 = 64<BR>\n" );
document.write( "10x + 4 = 64<BR>\n" );
document.write( "10x + 4 - 4 = 64 - 4<BR>\n" );
document.write( "10x = 60<BR>\n" );
document.write( "10x/10 = 60/10<BR>\n" );
document.write( "x = 6\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "(6 + 3) + (4(6) + 1) + 5(6) = 64<BR>\n" );
document.write( "9 + 25 + 30 = 64<BR>\n" );
document.write( "64 = 64 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );