document.write( "Question 792079: Flying against the wind, a jet travels 7290 miles in 9 hours. Flying with the wind, the same jet travels 3630 miles in 3 hours. What is the rate of the jet in still air and what is the rate of the wind? \n" ); document.write( "

Algebra.Com's Answer #479848 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 9 hours
\n" ); document.write( "with wind 3 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 7290 miles distance with 3630 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "7290.00 / ( x - y )= 9.00
\n" ); document.write( "9.00 ( x - y ) = 3.00
\n" ); document.write( "9.00 x - 9.00 y = 7290.00 ....................1
\n" ); document.write( "
\n" ); document.write( "3630.00 / ( x + y )= 3.00
\n" ); document.write( "3.00 ( x + y ) = 3630.00
\n" ); document.write( "3.00 x + 3.00 y = 3630.00 ...............2
\n" ); document.write( "Multiply (1) by 1.00
\n" ); document.write( "Multiply (2) by 3.00
\n" ); document.write( "we get
\n" ); document.write( "9.00 x + -9.00 y = 7290.00
\n" ); document.write( "9.00 x + 9.00 y = 10890.00
\n" ); document.write( "18.00 x = 18180.00
\n" ); document.write( "/ 18.00
\n" ); document.write( "x = 1010.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "9.00 x -9.00 y = 7290.00
\n" ); document.write( "9090.00 -9.00 -9090.00 = 7290.00
\n" ); document.write( "-9.00 y = 7290.00
\n" ); document.write( "-9.00 y = -1800.00 mph
\n" ); document.write( " y = 200.00
\n" ); document.write( "Plane speed 1010 mph
\n" ); document.write( "wind speed 200 mph
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

\n" );