document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=792008>Question 792008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a triangle has 2 sides that are the same length and a third side that's 10ft less than twice the shorter sides and the perimeter is 90 ft.write an equation and find the length of each side.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479840 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> side 1 and 2 = x<BR>\n" );
document.write( "side 3 = 2x - 10<BR>\n" );
document.write( "p = s * s * s<BR>\n" );
document.write( "90 = x + x + (2x -10)<BR>\n" );
document.write( "90 = 4x -10<BR>\n" );
document.write( "90 + 10 = 4x -10 + 10<BR>\n" );
document.write( "100 = 4x<BR>\n" );
document.write( "100/4 = 4x/4<BR>\n" );
document.write( "25 = x\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "90 = 25 + 25 + (2(25) -10)<BR>\n" );
document.write( "90 = 50 + 40<BR>\n" );
document.write( "90 = 90<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );