document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=791962>Question 791962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter is 44 cm. The length of a rectangle is 2 more than twice the witdth. Find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479807 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 2w + 2<BR>\n" );
document.write( "P = 2w + 2L<BR>\n" );
document.write( "44 = 2w + 2(w + 2)<BR>\n" );
document.write( "44 = 2w + 2w + 4<BR>\n" );
document.write( "44 - 4 = 4w + 4 - 4<BR>\n" );
document.write( "40 = 4w<BR>\n" );
document.write( "40 /4 = 4w/4<BR>\n" );
document.write( "10 = w\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "44 = 2(10) + 2(10 + 2)<BR>\n" );
document.write( "44 = 20 + 24<BR>\n" );
document.write( "44 = 44 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );