document.write( "Question 791967: Solve by substitution x+2y=7 4x-3y=-5 \n" ); document.write( "
Algebra.Com's Answer #479806 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! x + 2y = 7 \n" ); document.write( "4x - 3y = -5 \n" ); document.write( "multiply x + 2y = 7 by 4 to get 4x + 8y = 28 \n" ); document.write( "subtract the second equation from this new equation \n" ); document.write( "4x + 8y = 28 \n" ); document.write( "4x - 3y = -5 \n" ); document.write( "11y = 33 \n" ); document.write( "11y/11 = 33/11 \n" ); document.write( "y = 3\r \n" ); document.write( "\n" ); document.write( "first equation with value for y \n" ); document.write( "x + 2(3) = 7 \n" ); document.write( "x + 6 = 7 \n" ); document.write( "x + 6 - 6 = 7 - 6 \n" ); document.write( "x = 1\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "1 + 2(3) = 7 \n" ); document.write( "1 + 6 = 7 \n" ); document.write( "7 = 7\r \n" ); document.write( "\n" ); document.write( "4(1) - 3(3) = -5 \n" ); document.write( "4 - 9 = -5 \n" ); document.write( "-5 = -5 \n" ); document.write( " |