document.write( "Question 791917: Is the function 6x|2x^3| even, odd or neither ? and how to check solution ? \n" ); document.write( "
Algebra.Com's Answer #479790 by fcabanski(1391)\"\" \"About 
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Replace x with -x.


\n" ); document.write( "Even: f(x) = f(-x) and Odd: -f(x) = f(-x)


\n" ); document.write( "6(-x)*|2(-x)^3)| = -6x*|2x^3|: Absolute value is always positive, so the negative sign inside the absolute value drops.


\n" ); document.write( "6(-x)*|2(-x)^3)| = -f(x) (the whole function multiplied by -1). So it's an odd function.


\n" ); document.write( "You can check this easily by substituting 1 in for x. Compare it to using -1 for x, and 1 then multiplying the answer by -1.


\n" ); document.write( "f(1) = 6*1*|2*1^3| = 6*2 = 12


\n" ); document.write( "f(-1) = 6*(-1)*|2*(-1)^3| = -6*|-2| = -6*2 = -12


\n" ); document.write( "-f(1) = -12 = f(-1): Odd function.


\n" ); document.write( "You can also verify it by graphing the function. If the values on the left side of the y-acis (the values for -x's) are the same as the values on the right side, it is even. For example, the graph is at the same point when x=1 and when x=-1, x=2 and x=-2 etc.


\n" ); document.write( "If the values on the left side (positive x values) are opposites of the graph's values for the corresponding negative x values, then it's an odd function. For example when x=1 the graph is at (1,3), and when x = -1 the graph is at (-1,-3); (2,4), (-2,-4) etc. \n" ); document.write( "

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