document.write( "Question 791834: Prompt: In 1950, a city was first established containing 32,000 people. In the year 2000, the size of the city was 149,000 people.
\n" ); document.write( "Question A: determine the rate of change in the population.\r
\n" ); document.write( "\n" ); document.write( "Question B: Predict the size of the city in the year 2010.\r
\n" ); document.write( "\n" ); document.write( "My issue is that I don't understand how to do this problem. I thought it was 'y' over 'x' and this is what I got so far: 32000 divided by 1950 and 149000 divided by 2000 but I don't think is the right way to solve the issue. Please help me.
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Algebra.Com's Answer #479742 by wilft1(217)\"\" \"About 
You can put this solution on YOUR website!
lets put population on the y axis and year on the x axis... and find the slope which is m\r
\n" ); document.write( "\n" ); document.write( ".......y2 - y1
\n" ); document.write( "m =--------
\n" ); document.write( ".......x2 - x1\r
\n" ); document.write( "\n" ); document.write( "these are our two points
\n" ); document.write( "(1950,32000) and
\n" ); document.write( "(2000,149000)
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\n" ); document.write( " 149,000 - 32,000
\n" ); document.write( " -----------------
\n" ); document.write( " 2000 - 1950
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\n" ); document.write( "equals
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\n" ); document.write( " 117,000
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\n" ); document.write( " 50
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\n" ); document.write( "reduce to lowest terms...
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\n" ); document.write( "2340
\n" ); document.write( "----
\n" ); document.write( " 1
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\n" ); document.write( "so for every year, the population increases by 2340 people. to estimate the population for the year 2010, multiply 2340 by 10 = 23,400, add that to 149,000 to get an estimated population of 172,400 in the year 2010
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