document.write( "Question 66246: Please help sketch the graph and name the conic section with equation:
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document.write( "4x^2-16x+9y^2+18y=0 So far I have factored out the 4 and 9. What comes next?Thank you \n" );
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Algebra.Com's Answer #47972 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! I'm afraid the other solution that was posted for this problem is incorrect. Anytime you have an equation of a conic section with \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If both coefficients are the same sign with equal coefficients, it will be a CIRCLE. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If coefficients are of opposite sign, then it will be a HYPERBOLA. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A PARABOLA results when there is an \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is the way it should be solved by completing the square: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You must first factor out the coefficients of x^2 and y^2 like this: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is an ellipse. The standard form for an ellipse is in a form = 1, so divide both sides of the equation by 25 to set it equal to 1.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finally invert the coefficients of 4 and 9 in order to write this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That would be standard form for an ellipse! The center is at (2,-1), with the \"radius\" extending \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |