document.write( "Question 67414This question is from textbook Advanced mathematics
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document.write( ": Michelle had two containers, each containing a mixture of alcohol and disinfectant. One was 40% disinfectant and the other was 80% disinfectant. How much of each should be used to get 600 milliliters of a solution that is 50% disinfectant? \n" );
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Algebra.Com's Answer #47969 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x= amount of 80% \n" ); document.write( "Then 600-x= amount of 40%\r \n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure disinfectant in the 80% mixture (.8x) plus the amount of pure disinfectant in the 40% misture .4(600-x) must equal the amount of pure disinfectant in the final solution .5(600). So our equation to solve is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".8x+.4(600-x)=.5(600) simplifying we get\r \n" ); document.write( "\n" ); document.write( ".8x+240-.4x=300 subtract 240 from both sides and collect like terms:\r \n" ); document.write( "\n" ); document.write( ".4x=60 \n" ); document.write( "x=150 ml -----------------amount of 80% solution\r \n" ); document.write( "\n" ); document.write( "600-x=600-150=450 ml-----------amount of 40% solution\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "450(.4)+150(.8)=.5(600) \n" ); document.write( "180+120=300 \n" ); document.write( "300=300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |