document.write( "Question 791569: If 60 gallons of a 20% solution is needed and all that's available is a 10% solution and a40% solution how many of each is needed
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Algebra.Com's Answer #479630 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Solution I 10.00% ---------------- x gallons \n" ); document.write( "solution II 40.00% ------ 60 - x gallons \n" ); document.write( "Mixture 20.00% ---------------- 60 \n" ); document.write( "Total 60 gallons \n" ); document.write( "10.00% x + 40.00% ( 60 - x ) = 20.00% * 60 \n" ); document.write( "10 x + 40 ( 60 - x ) = 1200 \n" ); document.write( "10 x + 2400 - 40 x = 1200 \n" ); document.write( "10 x - 40 x = 1200 - -2400 \n" ); document.write( "-30 x = -1200 \n" ); document.write( "/ -30 \n" ); document.write( " x = 40 gallons 10.00% Solution I \n" ); document.write( " 20 gallons 40.00% solution II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |