document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67415>Question 67415</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1565770390/algebrahomeworkh>Advanced mathematics</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the number of reds to the number of blues was 2 to 1, and 5 times the sum of the number of reds and blues exceeded 3 times the number of whites by 12.  If there were 4 more whites than blues, how many were red, how many were white, and how many were blue? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47963 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We will let:\r<BR>\n" );
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document.write( "x=number of reds<BR>\n" );
document.write( "y=number of whites<BR>\n" );
document.write( "z=number of blues\r<BR>\n" );
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document.write( "Now we are told the following:<BR>\n" );
document.write( "x/z=2/1 cross multiply<BR>\n" );
document.write( "x=2z-------------------------our 1st equation\r<BR>\n" );
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document.write( "We are also told that:\r<BR>\n" );
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document.write( "5(x+z)=3y+12-----------------our 2nd equation\r<BR>\n" );
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document.write( "They also tell us:\r<BR>\n" );
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document.write( "y=z+4------------------------our 3rd equation\r<BR>\n" );
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document.write( "substitute x=2z into our 2nd eq. and we get\r<BR>\n" );
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document.write( "5(2z+z)=3y+12<BR>\n" );
document.write( "15z=3y+12  Now substitute y=z+4 into this equation:\r<BR>\n" );
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document.write( "15z=3(z+4)+12;<BR>\n" );
document.write( "15z=3z+12+12  subtract 3z from both sides and collect like terms;\r<BR>\n" );
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document.write( "12z=24<BR>\n" );
document.write( "z=2 ----------------------------------number of blue balls<BR>\n" );
document.write( "substitute z=2 into our 3rd eq.\r<BR>\n" );
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document.write( "y=z+4=2+4=6---------------------------number of white balls\r<BR>\n" );
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document.write( "substitute z=2 into our 1st eq\r<BR>\n" );
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document.write( "x=2z=2*2=4-----------------------------number of red balls\r<BR>\n" );
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document.write( "ck\r<BR>\n" );
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document.write( "(1)  ratio of red balls to blue balls is 2/1;  4/2=2/1 CHECKS<BR>\n" );
document.write( "(2)  5 times the sum of the number of reds and blues exceeded 3 times the number of whites by 12. 5*6-12=3*6  or 18=18-------CHECKS<BR>\n" );
document.write( "(3)  there were 4 more whites than blues 6-2=4   CHECKS\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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