document.write( "Question 791489: The radiator in Michelle’s car contains 16 L of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should she drain and replace with pure antifreeze so that there will be a mixture of 50% antifreeze? \n" ); document.write( "

Algebra.Com's Answer #479605 by josgarithmetic(39617) $\"\"$ $\"About$

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The volume will be the same before and after the adjustment.\r
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\n" ); document.write( "\n" ); document.write( "Let v = amount to remove and replace, in liters
\n" ); document.write( "Let P = current 30% antifreeze
\n" ); document.write( "let T = target 10% antifreeze wanted after adjustment
\n" ); document.write( "let C = 16 L, radiator capacity and current volume of antifreeze solution present\r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28%28C%2AP-v%2AP%2Bv%2A100%29%2FC=T%29\"$
\n" ); document.write( "Note that you add PURE antifreeze which is 100% antifreeze, and you add as much volume of this as the volume of the initial 30% antifreeze which is to be removed.\r
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\n" ); document.write( "\n" ); document.write( "SOLVE FOR v. \n" ); document.write( "

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