document.write( "Question 791358: I really need some help on the this problem. I have no idea how to solve it. Here it is: ***NOTE*** The ENTIRE second half of the equation is a FRACTION. It is the entire thing not just the -6 and 13. It is including the 2y also in the fraction. So the numerator would be -2y-(-6) and the denominator would just be 13. Please read this carefully so you do not change the problem. Thank you for your help because I have a BIG unit test tomorrow and need some help. Thanks! \r
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document.write( "2= -2y-(-6) / 13 \n" );
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Algebra.Com's Answer #479548 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you put parentheses around your quantities, then there is never any ambiguity about what your plain text rendering really means.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I surmise you want: 2 = (-2y - (-6))/13 which probably looks like\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remove the parentheses around the -6:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then multiply both sides by 13, add -6 to both sides, and finally multiply by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |