document.write( "Question 791320: \"x%2B6y=2\"
\n" ); document.write( "\"5x%2B4y=36\"\r
\n" ); document.write( "\n" ); document.write( "I have been trying to use substitution to solve the system. I do as I was taught and on the first equation subtract 6y from both sides to find my X equation. Every time I plug in x=2-6y I keep getting y=0 which is not correct because I have checked. I also get x=2. No matter how many times I work it the answer is still the same. I would like to know how you get the correct answer, which is in the back of my math book, (8, -1) Thank you.
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Algebra.Com's Answer #479530 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
solve the first equation for x to get\r
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\n" ); document.write( "\n" ); document.write( "x+6y=2\r
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\n" ); document.write( "\n" ); document.write( "x=2-6y\r
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\n" ); document.write( "\n" ); document.write( "then plug this into the second equation\r
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\n" ); document.write( "\n" ); document.write( "5x+4y=36\r
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\n" ); document.write( "\n" ); document.write( "5(2 - 6y)+4y=36\r
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\n" ); document.write( "\n" ); document.write( "10 - 30y+4y=36\r
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\n" ); document.write( "\n" ); document.write( "10-28y=36\r
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\n" ); document.write( "\n" ); document.write( "-26y=36-10\r
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\n" ); document.write( "\n" ); document.write( "-26y=26\r
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\n" ); document.write( "\n" ); document.write( "y = 26/(-26)\r
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\n" ); document.write( "\n" ); document.write( "y = -1\r
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\n" ); document.write( "\n" ); document.write( "And then use this to find x\r
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\n" ); document.write( "\n" ); document.write( "x=2-6y\r
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\n" ); document.write( "\n" ); document.write( "x=2-6(-1)\r
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\n" ); document.write( "\n" ); document.write( "x=2+6\r
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\n" ); document.write( "\n" ); document.write( "x = 8\r
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\n" ); document.write( "\n" ); document.write( "So that shows you why the answer is (8,-1)
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