document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=791221>Question 791221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What come Next in the series 98,14,2,2/7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479468 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The rule is that you multiply each term by 1/7 to get the next term. Multiply the last term by 1/7 to get (2/7)*(1/7) = (2*1)/(7*7) = <font color=\"red\">2/49</font> </SPAN>\n" );
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