document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=791164>Question 791164</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 1 foot less than twice the width. perimeter is 40 feet. find dimensions.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479412 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2w + 2L<BR>\n" );
document.write( "L = 2w -1\r<BR>\n" );
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document.write( "40 = 2w + 2(2w -1)<BR>\n" );
document.write( "40 = 2w + 4w -2<BR>\n" );
document.write( "40 + 2 = 6w -2 + 2<BR>\n" );
document.write( "42 = 6w<BR>\n" );
document.write( "42/6 = 6w/6<BR>\n" );
document.write( "7 = w<BR>\n" );
document.write( "width = 7 feet<BR>\n" );
document.write( "length = 2(7) -1<BR>\n" );
document.write( "       = 14 -1<BR>\n" );
document.write( "       = 13 feet\r<BR>\n" );
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document.write( "check: <BR>\n" );
document.write( "40 = 2(7) + 2(13)<BR>\n" );
document.write( "40 = 14 + 26<BR>\n" );
document.write( "40 = 40  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );