document.write( "Question 67391This question is from textbook
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document.write( ": 2/5x +1 = 1-x
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document.write( "On both sides of the equal sign are absolute value brackets. What I'm unsure of is, what or how do I get rid of the fraction 2/5x ?
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document.write( "Thanks,
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document.write( "Bob \n" );
document.write( "
Algebra.Com's Answer #47939 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! |(2/5)x +1| = |1-x| \n" ); document.write( "Find the zero values. \n" ); document.write( "(2/5)x+1=0 \n" ); document.write( "x=-5/2 \n" ); document.write( "---------- \n" ); document.write( "1-x=0 \n" ); document.write( "x=1 \n" ); document.write( "------------ \n" ); document.write( "Draw a number line and mark two points as -5/2 and 1. \n" ); document.write( "This breaks the number line into three segments. We \n" ); document.write( "need to look for solutions in each segment, keeping in \n" ); document.write( "mind the definition of absolute value. \n" ); document.write( "------------------------------------ \n" ); document.write( "In the segment (-inf,-5/2) you get: \n" ); document.write( "-(2/5x+1)=1-x \n" ); document.write( "(2/5)x+1=x-1 \n" ); document.write( "(3/5)x=2 \n" ); document.write( "x=10/3 \n" ); document.write( "------------- \n" ); document.write( "In the segment (-5/2,1) you get: \n" ); document.write( "(2/5)x+1=1-x \n" ); document.write( "(7/5)x=0 \n" ); document.write( "x=0 \n" ); document.write( "------------- \n" ); document.write( "In the segment (1,inf) you get: \n" ); document.write( "(2/5)x+1 = x-1 \n" ); document.write( "-(3/5)x=-2 \n" ); document.write( "(3/5)x=2 \n" ); document.write( "x=10/3 \n" ); document.write( "------------- \n" ); document.write( "Check these answers: \n" ); document.write( "If x=0, |(2/5)x+1| = 1 = |1-x| \n" ); document.write( "If x=10/3, |(2/5)x+1] = |4/3+3/3| = 7/3 = |10/3-1|\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |