document.write( "Question 67391This question is from textbook
\n" ); document.write( ": 2/5x +1 = 1-x
\n" ); document.write( "On both sides of the equal sign are absolute value brackets. What I'm unsure of is, what or how do I get rid of the fraction 2/5x ?
\n" ); document.write( "Thanks,
\n" ); document.write( "Bob
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Algebra.Com's Answer #47939 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
|(2/5)x +1| = |1-x|
\n" ); document.write( "Find the zero values.
\n" ); document.write( "(2/5)x+1=0
\n" ); document.write( "x=-5/2
\n" ); document.write( "----------
\n" ); document.write( "1-x=0
\n" ); document.write( "x=1
\n" ); document.write( "------------
\n" ); document.write( "Draw a number line and mark two points as -5/2 and 1.
\n" ); document.write( "This breaks the number line into three segments. We
\n" ); document.write( "need to look for solutions in each segment, keeping in
\n" ); document.write( "mind the definition of absolute value.
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\n" ); document.write( "In the segment (-inf,-5/2) you get:
\n" ); document.write( "-(2/5x+1)=1-x
\n" ); document.write( "(2/5)x+1=x-1
\n" ); document.write( "(3/5)x=2
\n" ); document.write( "x=10/3
\n" ); document.write( "-------------
\n" ); document.write( "In the segment (-5/2,1) you get:
\n" ); document.write( "(2/5)x+1=1-x
\n" ); document.write( "(7/5)x=0
\n" ); document.write( "x=0
\n" ); document.write( "-------------
\n" ); document.write( "In the segment (1,inf) you get:
\n" ); document.write( "(2/5)x+1 = x-1
\n" ); document.write( "-(3/5)x=-2
\n" ); document.write( "(3/5)x=2
\n" ); document.write( "x=10/3
\n" ); document.write( "-------------
\n" ); document.write( "Check these answers:
\n" ); document.write( "If x=0, |(2/5)x+1| = 1 = |1-x|
\n" ); document.write( "If x=10/3, |(2/5)x+1] = |4/3+3/3| = 7/3 = |10/3-1|\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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