document.write( "Question 791003: the sum of the digits of a three digit number is 9. if the digits are reversed the number increases by 495. Find the number if the sum of the tens and hundreds digits is half the units digit.\r
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Algebra.Com's Answer #479364 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
the sum of the digits of a three digit number is 9. if the digits are reversed the number increases by 495. Find the number if the sum of the tens and hundreds digits is half the units digit.
\n" ); document.write( "let u=units digit
\n" ); document.write( "let t=tens digit
\n" ); document.write( "let h=hundreds digit
\n" ); document.write( "..
\n" ); document.write( "h+t+u=9
\n" ); document.write( "h+t=u/2
\n" ); document.write( "(u/2)+u=9
\n" ); document.write( "3u/2=9
\n" ); document.write( "3u/18
\n" ); document.write( "u=6
\n" ); document.write( "original number:
\n" ); document.write( "100h+10t+6
\n" ); document.write( "..
\n" ); document.write( "reversed number:
\n" ); document.write( "600+10t+h
\n" ); document.write( "..
\n" ); document.write( "reverse-original number=495
\n" ); document.write( "600+10t+h-(100h+10t+6)=495
\n" ); document.write( "594-99h=495
\n" ); document.write( "99h=99
\n" ); document.write( "h=1
\n" ); document.write( "t=9-h-u=9-7=2
\n" ); document.write( "original number:100h+10t+6=126
\n" ); document.write( "reversed number=621
\n" ); document.write( "check:621-126=495\r
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