document.write( "Question 790966: A boat can travel 24 mi in 3 h when traveling with a current. against the same current, it can travel only 16 mi in 4 h. find the rate of the current and the rate of the boat in still water. \n" ); document.write( "
Algebra.Com's Answer #479340 by lwsshak3(11628)\"\" \"About 
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A boat can travel 24 mi in 3 h when traveling with a current. against the same current, it can travel only 16 mi in 4 h. find the rate of the current and the rate of the boat in still water.
\n" ); document.write( "***
\n" ); document.write( "let x=rate of boat in still water
\n" ); document.write( "let c=rate of current
\n" ); document.write( "x+c=rate of boat when traveling with the current
\n" ); document.write( "x-c=rate of boat when traveling against the current
\n" ); document.write( "..
\n" ); document.write( "traveling 24 mi in 3hr=8 mi/hr
\n" ); document.write( "traveling 16 mi in 4hr=4 mi/hr
\n" ); document.write( "..
\n" ); document.write( "2 equations:
\n" ); document.write( "8=x+c (with current)
\n" ); document.write( "4=x-c (against current)
\n" ); document.write( "add
\n" ); document.write( "12=2x
\n" ); document.write( "x=6
\n" ); document.write( "c=2
\n" ); document.write( "..
\n" ); document.write( "rate of boat in still water=6 mi/hr
\n" ); document.write( "rate of current=2 mi/hr \n" ); document.write( "
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