document.write( "Question 790553: 16 / (x+2) = 1 + 2/(x-4)\r
\n" ); document.write( "\n" ); document.write( "I first eliminated the denominator x+2, then the denominator x-4. Simplifying and setting equal to 0, I get x = -6, -10. These solutions do not work, but their positives do. I don't understand how to solve this equation without getting negative values for x.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance.
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Algebra.Com's Answer #479303 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I get 6 and 10.
\n" ); document.write( "You must have made some small mistake.
\n" ); document.write( "It is very hard to notice one's own mistakes.
\n" ); document.write( "\"16+%2F+%28x%2B2%29+=+1+%2B+2%2F%28x-4%29\"
\n" ); document.write( "Multiplying both sides times \"%28x%2B2%29%28x-4%29\" I get
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\n" ); document.write( "which simplifies to
\n" ); document.write( "\"16%28x-4%29+=+%28x%2B2%29%28x-4%29+%2B+2%28x%2B2%29\"
\n" ); document.write( "\"16x-64+=+x%5E2-2x-8+%2B+2x%2B4\"
\n" ); document.write( "\"16x-64+=+x%5E2+-8+%2B4\"
\n" ); document.write( "\"16x-64+=+x%5E2-4\"
\n" ); document.write( "\"0+=+x%5E2-4-16x%2B64\"
\n" ); document.write( "\"x%5E2-16x%2B60=0\"
\n" ); document.write( "Factoring, I get
\n" ); document.write( "\"%28x-6%29%28x-10%29=0\"
\n" ); document.write( "So, either \"x-6=0\" --> \"highlight%28x=6%29\",
\n" ); document.write( "or \"x-10=0\" --> \"highlight%28x=10%29\".
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\n" ); document.write( "If you do not like factoring, you could use the quadratic formula, or \"complete the square\" instead.
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\n" ); document.write( "Completing the square:
\n" ); document.write( "\"x%5E2-16x%2B60=0\"
\n" ); document.write( "\"x%5E2-16x=-60\"
\n" ); document.write( "\"x%5E2-16x%2B64=-60%2B64\"
\n" ); document.write( "\"%28x-8%29%5E2=4\"
\n" ); document.write( "So either \"x-8=2\" --> \"x=2%2B8\" --> \"highlight%28x=10%29\",
\n" ); document.write( "or \"x-8=-2\" --> \"x=-2%2B8\" --> \"highlight%28x=6%29\"
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\n" ); document.write( "Using the quadratic formula:
\n" ); document.write( "The solutions to \"ax%5E2%2Bbx%2Bc=0\" are given by \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\".
\n" ); document.write( "In the case of \"x%5E2-16x%2B60=0\",
\n" ); document.write( "\"a=1\", \"b=-16\", and \"c=60\", so
\n" ); document.write( ".
\n" ); document.write( "The solutions are
\n" ); document.write( "\"x=%2816+%2B+4%29%2F2=20%2F2=highlight%28x=10%29\"
\n" ); document.write( "and \"x=%2816+-+4%29%2F2=12%2F2=highlight%28x=6%29\"
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