document.write( "Question 790782: solve the system\r
\n" ); document.write( "\n" ); document.write( "3y-4x=12
\n" ); document.write( "y-2x=4\r
\n" ); document.write( "\n" ); document.write( "how do I do this?\r
\n" ); document.write( "\n" ); document.write( "help would be greatly appreciated\r
\n" ); document.write( "\n" ); document.write( "thank you \n" ); document.write( "
Algebra.Com's Answer #479292 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
solve the system\r
\n" ); document.write( "\n" ); document.write( "3y-4x=12
\n" ); document.write( "y-2x=4\r
\n" ); document.write( "\n" ); document.write( "how do I do this?
\n" ); document.write( "================
\n" ); document.write( "There's more than 1 way.
\n" ); document.write( "Substitution is 1 method.
\n" ); document.write( "---
\n" ); document.write( "y-2x=4
\n" ); document.write( "y = 2x + 4
\n" ); document.write( "Sub for y in the 1st eqn
\n" ); document.write( "---
\n" ); document.write( "3y - 4x = 12
\n" ); document.write( "3(2x+4) - 4x = 12
\n" ); document.write( "Solve for x.
\n" ); document.write( "6x + 12 - 4x = 12
\n" ); document.write( "2x = 0
\n" ); document.write( "x = 0
\n" ); document.write( "-----------------
\n" ); document.write( "Then solve for y.
\n" ); document.write( "-----------
\n" ); document.write( "y = 2x + 4
\n" ); document.write( "y = 4
\n" ); document.write( " \n" ); document.write( "
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