document.write( "Question 790701: Solve: 12x^3 + 12x^2 - 9x = 0\r
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document.write( "I forgot how to factor when the first term has an exponent of 3...\r
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document.write( "Here is what I have so far which isn't much.\r
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document.write( "3x(3x^2 + 3)(4x - 3)......what do I do from here if this is even right.\r
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document.write( "Can I factor (3x^2 + 3) more? I know I'm supposed to have at least 3 answers for this problem. \n" );
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Algebra.Com's Answer #479260 by shosta(4)![]() ![]() ![]() You can put this solution on YOUR website! 12x^3 + 12x^2 - 9x = 0 \n" ); document.write( "okay so first, you were correct in your assumption that we could factor a 3x out, but the rest was incorrect \r \n" ); document.write( "\n" ); document.write( "after we factor a 3x out of every term we are left with \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to factor 4x^2+4x-3 we look at the multiples of the first and last terms (4 and 3) and try to make them add or subtract to equal the middle term (4). Since out last term is negative this means our answer is going to involve subtraction and be in the form (#X - #)(#X + #). \r \n" ); document.write( "\n" ); document.write( "so the factors of 4 are 1X4 2X2 \n" ); document.write( "the factors of 3 are 1X3 \r \n" ); document.write( "\n" ); document.write( "so we try to arrange these terms in a way that will give us back the same equation we had before when we multiply it out\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " to check to make sure this is the correct order we can foil it out and make sure it matches the original, if not rearrange the terms and foil again \r \n" ); document.write( "\n" ); document.write( "now don't forget to put the 3x back up there \n" ); document.write( "so you have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |