document.write( "Question 67383This question is from textbook Advanced mathematics
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document.write( ": Solve for x:\r
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document.write( "A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)\r
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document.write( "B.)log(base 7)6 -log(base 7)(x-1) = log(base 7)3\r
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document.write( "C.)3log(base x)4 = 2 \n" );
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Algebra.Com's Answer #47923 by algebrapro18(249)![]() ![]() ![]() You can put this solution on YOUR website! A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5) \n" ); document.write( "Log(base 3)20 = log(base 3)(4x+5) \n" ); document.write( "Log(base 3)20 - log(base 3)(4x+5) = 0 \n" ); document.write( "Log(base 3)20/(4x+5) = 0 \n" ); document.write( "3^0 = 20/(4x+5) \n" ); document.write( "1 = 20/(4x+5) \n" ); document.write( "4x+5 = 20 \n" ); document.write( "4x = 15 \n" ); document.write( "x = 15/4 \r \n" ); document.write( "\n" ); document.write( "B.)log(base 7)6 -log(base 7)(x-1) = log(base 7)3 \n" ); document.write( "log(base 7)6/(x-1) = log(base 7)3 \n" ); document.write( "log(base 7)6/(x-1) - log(base 7)3 = 0 \n" ); document.write( "log(base 7)6/3(x-1) = 0 \n" ); document.write( "7^0 = 6/3(x-1) \n" ); document.write( "1 = 6/3(x-1) \n" ); document.write( "3x-3 = 6 \n" ); document.write( "3x = 0 \n" ); document.write( "x = 3 \r \n" ); document.write( "\n" ); document.write( "C.)3log(base x)4 = 2 \n" ); document.write( "log(base x)64 = 2 \n" ); document.write( "x^2 = 64 \n" ); document.write( "x = +/- 8 \n" ); document.write( " |