document.write( "Question 790606: \" Y = 1.5x - 3 \"\r
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Algebra.Com's Answer #479220 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Plug in x = 0 to get \r
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\n" ); document.write( "\n" ); document.write( "y = 1.5x - 3 \r
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\n" ); document.write( "\n" ); document.write( "y = 1.5*0 - 3 \r
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\n" ); document.write( "\n" ); document.write( "y = 0 - 3 \r
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\n" ); document.write( "\n" ); document.write( "y = -3 \r
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\n" ); document.write( "\n" ); document.write( "So the point (0,-3) is on the line\r
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\n" ); document.write( "\n" ); document.write( "Plug in x = 2 to get \r
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\n" ); document.write( "\n" ); document.write( "y = 1.5x - 3 \r
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\n" ); document.write( "\n" ); document.write( "y = 1.5*2 - 3 \r
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\n" ); document.write( "\n" ); document.write( "y = 3 - 3 \r
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\n" ); document.write( "\n" ); document.write( "y = 0 \r
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\n" ); document.write( "\n" ); document.write( "So the point (2,0) is on the line\r
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\n" ); document.write( "y = 1.5x - 3\r
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\n" ); document.write( "\n" ); document.write( "We know the points (0,-3) and (2,0) are on the line. Plot these two points. Then draw a straight line through them to finish the graph (see graph below)\r
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