document.write( "Question 790601: \"Suppose that one cocktail is 25% ethanol and another cocktail is 110% ethanol. How many milliliters of each solution should be mixed to make 10.5 milliliters of an 80% ethanol solution\"?\r
\n" ); document.write( "\n" ); document.write( "Can I get help with setting up an equation and solving please?\r
\n" ); document.write( "\n" ); document.write( "Thank you for your time.
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Algebra.Com's Answer #479219 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
we are given
\n" ); document.write( ".25x solution and a 1.10y solution
\n" ); document.write( "x+y = 10.5 mL
\n" ); document.write( ".80 * 10.5 = 8.4 mL
\n" ); document.write( "now we can solve for x
\n" ); document.write( "x = 10.5 - y and substituting for x we have
\n" ); document.write( ".25*(10.5-y) + 1.10*y = 8.4
\n" ); document.write( "2.65 -.25y + 1.10y = 8.4
\n" ); document.write( ".85y = 5.75
\n" ); document.write( "y = 6.76 mL and
\n" ); document.write( "x = 10.5 - 6.76 = 3.74 mL
\n" ); document.write( "check the answers
\n" ); document.write( ".25(3.74) + 1.10(6.76) = 8.4
\n" ); document.write( ".935 + 7.436 = 8.4
\n" ); document.write( "8.4 = 8.4\r
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