document.write( "Question 790601: \"Suppose that one cocktail is 25% ethanol and another cocktail is 110% ethanol. How many milliliters of each solution should be mixed to make 10.5 milliliters of an 80% ethanol solution\"?\r
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document.write( "Can I get help with setting up an equation and solving please?\r
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document.write( "Thank you for your time. \n" );
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Algebra.Com's Answer #479219 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! we are given \n" ); document.write( ".25x solution and a 1.10y solution \n" ); document.write( "x+y = 10.5 mL \n" ); document.write( ".80 * 10.5 = 8.4 mL \n" ); document.write( "now we can solve for x \n" ); document.write( "x = 10.5 - y and substituting for x we have \n" ); document.write( ".25*(10.5-y) + 1.10*y = 8.4 \n" ); document.write( "2.65 -.25y + 1.10y = 8.4 \n" ); document.write( ".85y = 5.75 \n" ); document.write( "y = 6.76 mL and \n" ); document.write( "x = 10.5 - 6.76 = 3.74 mL \n" ); document.write( "check the answers \n" ); document.write( ".25(3.74) + 1.10(6.76) = 8.4 \n" ); document.write( ".935 + 7.436 = 8.4 \n" ); document.write( "8.4 = 8.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |