document.write( "Question 790518: Given the sequence of first differences: 8, 10, 12, 14 find the first six terms of the original sequence if the sum of the third and fourth terms of the original sequence is 40 \n" ); document.write( "

Algebra.Com's Answer #479179 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "The difference between

and

is 12 from the sequence of first differences, and the sum of

and

is given as 40. That is a 2X2 system. Solve the 2X2 system for

and

, then the rest should just fall into place.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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