document.write( "Question 790009: Stuck need help with this problem:\r
\n" ); document.write( "\n" ); document.write( "A chemist needs a 110 mL of 32% solution, but only has 29% & 40% solutions available. How much of each solution does he need?\r
\n" ); document.write( "\n" ); document.write( "Can you please walk me thru this to help me get the answer?
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Algebra.Com's Answer #479112 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Stuck need help with this problem:\r
\n" ); document.write( "\n" ); document.write( "A chemist needs a 110 mL of 32% solution, but only has 29% & 40% solutions available. How much of each solution does he need?\r
\n" ); document.write( "\n" ); document.write( "Can you please walk me thru this to help me get the answer?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let amount of 29% to be used be T
\n" ); document.write( "Then amount of 40% to be used = 110 – T
\n" ); document.write( "Therefore, .29T + .4(110 – T) = .32(T + 110 – T)
\n" ); document.write( ".29T + 44 - .4T = .32T + 35.2 - .32T
\n" ); document.write( ".29T - .4T = 35.2 – 44
\n" ); document.write( "- .11T = - 8.8
\n" ); document.write( "T, amount of 29% solution to be used = \"%28-+8.8%29%2F-.11\", or \"880%2F11\", or \"highlight_green%2880%29\" mL\r
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\n" ); document.write( "\n" ); document.write( "Amount of 40% solution to be used = 110 - 80, or \"highlight_green%2830%29\" mL\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "\n" ); document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com. Further help is available, online or in-person, for a fee, obviously. \r
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