document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=790000>Question 790000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help me figure this out, <BR>\n" );
document.write( "In a triangle, two sides that measure 6 cm and 10 cm form an angle that measures 80 degrees. Find, to the nearest degree, the measure of the smallest angle in the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #479032 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=479032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the law of cosines to find the length of the third side<BR>\n" );
document.write( "c^2 = 10^2 + 6^2 - 2*10*6(cos(80))<BR>\n" );
document.write( "c^2 = 136 -120*.17<BR>\n" );
document.write( "c^2 = 136 -20.84<BR>\n" );
document.write( "c = 10.7<BR>\n" );
document.write( "now use the law of sines<BR>\n" );
document.write( "a/sin(A) = b/sin(B) = c / sin(C)<BR>\n" );
document.write( "10.7 / sin(80) = 10 / sin(B) = 6 / sin(C)<BR>\n" );
document.write( "sin(B) = 10 / 10.7 = .934<BR>\n" );
document.write( "sin(69) = .934<BR>\n" );
document.write( "now<BR>\n" );
document.write( "80 + 69 = 149 and<BR>\n" );
document.write( "180 - 149 = 31<BR>\n" );
document.write( "therefore the smallest angle is 31 degrees\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );