document.write( "Question 789983: Having trouble with this concept.Category is \"replacement sets\" the question posed is- b-(-3b-3)=4b+3.the correct set is 2.....but then the confusion with me is-again-2-(-6-3) which is-2-(-9)=11? the other side of equation is ok(11 of course).Is it because the 2 negative signs(one inside parenthesis)and the positive 2 in front makes the 9 positive???? One final question-any number inside absolute value sign will become positive-if the number is negative....but positive number cannot become negative? \n" ); document.write( "
Algebra.Com's Answer #479002 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " as you said, the other side of equation is ok(11 of course).Is it because the 2 negative signs(one inside parenthesis)and the positive 2 in front makes the 9 positive--this is \n" ); document.write( "\n" ); document.write( "now, your question: any number inside absolute value sign will become positive-if the number is negative \r \n" ); document.write( "\n" ); document.write( "that is \n" ); document.write( "\n" ); document.write( "the absolute value of a number is the \n" ); document.write( "\n" ); document.write( "example: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |