document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=789860>Question 789860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if two opposite side of a square are each increased by 3centimeters, and the other sides are each decreased by 2centimeters , the area is increased by 8 square centimeters. find the length of a side of the square.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478957 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> side of square=x\r<BR>\n" );
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document.write( "side after increase = x+3\r<BR>\n" );
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document.write( "other side = x-2<BR>\n" );
document.write( "area = (x+3)(x-2)\r<BR>\n" );
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document.write( "(x+3)(x-2)=x^2+8\r<BR>\n" );
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document.write( "x^2+x-6 =x^2+8\r<BR>\n" );
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document.write( "x-6 =8\r<BR>\n" );
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document.write( "x=6+8<BR>\n" );
document.write( "x=14 cm side of square </SPAN>\n" );
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