document.write( "Question 789490: Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y \n" ); document.write( "
Algebra.Com's Answer #478947 by lwsshak3(11628)\"\" \"About 
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Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y
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\n" ); document.write( "This is an equation of a parabola that opens down with vertex at the origin.
\n" ); document.write( "Its basic form: x^2=-4py
\n" ); document.write( "For given parabola:
\n" ); document.write( "axis of symmetry: x=0
\n" ); document.write( "4p=2
\n" ); document.write( "p=1/2
\n" ); document.write( "focus: (0,-1/2) (p-distance below vertex on the axis of symmetry)
\n" ); document.write( "Directrix: y=1/2 (p-distance above vertex on the axis of symmetry)
\n" ); document.write( "see graph below:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%5E2%2F2%29+\"
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