document.write( "Question 789490: Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y \n" ); document.write( "
Algebra.Com's Answer #478947 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y \n" ); document.write( "*** \n" ); document.write( "This is an equation of a parabola that opens down with vertex at the origin. \n" ); document.write( "Its basic form: x^2=-4py \n" ); document.write( "For given parabola: \n" ); document.write( "axis of symmetry: x=0 \n" ); document.write( "4p=2 \n" ); document.write( "p=1/2 \n" ); document.write( "focus: (0,-1/2) (p-distance below vertex on the axis of symmetry) \n" ); document.write( "Directrix: y=1/2 (p-distance above vertex on the axis of symmetry) \n" ); document.write( "see graph below: \n" ); document.write( " |