document.write( "Question 789807: Sarah Meeham blends coffee for Tasti-Delight. She needs to prepare 150lbs of blended coffee beans selling for $5.17 per pound. She plans to do this by blending together a high quality bean costing $6.00 per pound and a cheaper bean costing $3.50 a pound. To the nearest pound, find how much high quality bean and how much cheaper coffee bean she should use.\r
\n" ); document.write( "\n" ); document.write( "Hello! I was assuming that my equation would be something similar to 6x + 3.50y = 5.17... but I'm not sure how to incorporate and figure out the 150 lbs part? Help? Thank you!
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Algebra.Com's Answer #478942 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
This is a mixture problem involving price and cost. The target is about finding a price of resulting blend which becomes 5.17 DOLLARS per POUND.\r
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\n" ); document.write( "\n" ); document.write( "{cost of blend}/{pounds of blend}={price of blend}\r
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\n" ); document.write( "\n" ); document.write( "Let x = pounds of the 6 dollar a pound coffee
\n" ); document.write( "Let y = pounds of the 3.5 dollar a pound coffee\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%286x%2B3.5y%29%2F%28150%29=5.17%29\" AND \"highlight%28x%2By=150%29\"\r
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\n" ); document.write( "\n" ); document.write( "YES. TWO Equations. They are both linear equations. Work with the ratio equation so it is either easier to use for substitution or so it is in Standard Form:\r
\n" ); document.write( "\n" ); document.write( "\"6x%2B3.5y=150%285.17%29\"
\n" ); document.write( "Subtract 6 of the mass sum equation from this price equation to solve for y:
\n" ); document.write( "\"6x%2B3.5y-%286x%2B6y%29=150%285.17%29-6%28150%29\"
\n" ); document.write( "\"-2.5y=150%285.17-6%29\"
\n" ); document.write( "\"2.5y=150%286-5.17%29\"
\n" ); document.write( "\"2.5y=150%280.83%29\"
\n" ); document.write( "\"y=%281%2F2.5%29150%280.83%29\"
\n" ); document.write( "\"y=49.8\" pounds
\n" ); document.write( "Now find the other value higher priced coffee, \"x=100.2\"\r
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\n" ); document.write( "\n" ); document.write( "To nearest pound,
\n" ); document.write( "\"highlight%28x=100%29\" pounds, the more expensive coffee
\n" ); document.write( "\"highlight%28y=50%29\" pounds, the cheaper coffee
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