document.write( "Question 789724: Let the width of a rectangle be w. The length of the rectangle is six less than double the width.
\n" ); document.write( "A.) Write an equation to represent the area.
\n" ); document.write( "B.) Write an expression to represent the perimeter.
\n" ); document.write( "C.) Solve the equation if the perimeter is 30 inches.
\n" ); document.write( "D.) Tell the dimensions of the rectangle.
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Algebra.Com's Answer #478939 by waynest(281)\"\" \"About 
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l = 2w - 6\r
\n" ); document.write( "\n" ); document.write( "A.) A = lw
\n" ); document.write( " A = w(2w - 6)
\n" ); document.write( " A = 2w^2 - 6w\r
\n" ); document.write( "\n" ); document.write( "B.) P = 2L + 2w
\n" ); document.write( " P = 2(2w - 6) + 2w
\n" ); document.write( " P = (4w - 12) + 2w
\n" ); document.write( " P = 6w -12\r
\n" ); document.write( "\n" ); document.write( "C.) 30 = 6w - 12
\n" ); document.write( " 30 + 12 = 6w - 12 + 12
\n" ); document.write( " 42 = 6w
\n" ); document.write( " 42/6 = 6w /6
\n" ); document.write( " 7 = w\r
\n" ); document.write( "\n" ); document.write( "D.) width = 7 inches
\n" ); document.write( " length = 2(7) - 6 = 8 inches
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