document.write( "Question 789776: I really have no idea how to solve this. Any help would be appreciated. Thanks\r
\n" ); document.write( "\n" ); document.write( "When hired at a new job selling jewelry, you are given two pay options:\r
\n" ); document.write( "\n" ); document.write( "Option A: Base salary of $18,000 a year, with a commission of 9% of your sales\r
\n" ); document.write( "\n" ); document.write( "Option B: Base salary of $26,000 a year, with a commission of 2% of your sales\r
\n" ); document.write( "\n" ); document.write( "In order for option A to produce a larger income, you would need sell at least $...
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Algebra.Com's Answer #478935 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Option A: Base salary of $18,000 a year, with a commission of 9% of your sales\r
\n" ); document.write( "\n" ); document.write( "Option B: Base salary of $26,000 a year, with a commission of 2% of your sales\r
\n" ); document.write( "\n" ); document.write( "Let us assume I have to sell worth $x\r
\n" ); document.write( "\n" ); document.write( "Option A sales - option B sales\r
\n" ); document.write( "\n" ); document.write( "Income from A >Income from B\r
\n" ); document.write( "\n" ); document.write( "18000 +0.09*x >26000+0.02x\r
\n" ); document.write( "\n" ); document.write( "18000-26000>0.02x-0.09x\r
\n" ); document.write( "\n" ); document.write( "-8000>-0.07x\r
\n" ); document.write( "\n" ); document.write( "-8000/-0.07 \n" ); document.write( "\n" ); document.write( "114,286\n" ); document.write( "\n" ); document.write( "Sales should be less than 114,286 for option A to be better\r
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