document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=789771>Question 789771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a quadrilateral is 160, the sides are (4m^2+1), (3m-4), (2m+6), (4m^2+2m+1)\r<BR>\n" );
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document.write( "Please help, thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478931 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a quadrilateral is 160, the sides are <BR>\n" );
document.write( "(4m^2+1), (3m-4), (2m+6), (4m^2+2m+1) <BR>\n" );
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document.write( "Add those to get 8m^2+ 7m + 4 = 160<BR>\n" );
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document.write( "8m^2 +7m - 156 = 0<BR>\n" );
document.write( "m = 4<BR>\n" );
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document.write( "4m^2+1 = 65<BR>\n" );
document.write( "3m-4 = 8<BR>\n" );
document.write( "2m+6 = 14<BR>\n" );
document.write( "4m^2+2m+1 = 73<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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