document.write( "Question 789692: How many pounds of a chicken feed that sells for $5 a lb. must be mixed with 400 pounds of a feed
\n" ); document.write( "that sells for $8 a lb.to make a chicken feed that sells for $7.50 a lb.? 5x+8x/400=7.50
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Algebra.Com's Answer #478904 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Pay closer attention to cost and pounds. This is a mixture problem and the concentration is DOLLARS per POUND. Your target is 7.50 dollars per pound.\r
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\n" ); document.write( "\n" ); document.write( "Using the variable choices as you tried,
\n" ); document.write( "x = pounds of the lower priced feed
\n" ); document.write( "y = pounds of the higher priced feed, but you do NOT need this as variable.\r
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\n" ); document.write( "\n" ); document.write( "Already you were given to start with 400 pounds of the 8$/pound feed.\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28%285x%2B8%2A400%29%2F%28x%2B400%29=7.50%29\"
\n" ); document.write( "SOLVE FOR x.\r
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\n" ); document.write( "\n" ); document.write( "SOME INSTRUCTION---------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "DEVELOP THE EQUATION:\r
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\n" ); document.write( "\n" ); document.write( "{COST OF MIXTURE}/{AMOUNT OF MIXTURE}={PRICE FOR MIXTURE}\r
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\n" ); document.write( "\n" ); document.write( "You know the amount of the $8/pound chicken feed, 400 pounds.
\n" ); document.write( "The amount of the $5/pound feed is unknown variable, x.
\n" ); document.write( "Cost for the mixture is 5x+8*400 dollars.\r
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\n" ); document.write( "\n" ); document.write( "The amount of mixture is a variable expression, x+400.\r
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\n" ); document.write( "\n" ); document.write( "You want the PRICE of the mixture to be 7.50 dollars per pound.\r
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\n" ); document.write( "\n" ); document.write( "Put this altogether and make \"%285x%2B8%2A400%29%2F%28x%2B400%29=7.50\".\r
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\n" ); document.write( "\n" ); document.write( "You clear the \"fraction\" by doing something to BOTH sides of the equation. This means, multiply left and right sides by (x+400); simplify if you wish. You are initially relying on the idea, \"n%2Fd=c\" being equivalent to \"%28n%2Fd%29%28d%29=cd\", which would be \"n=cd\". (Generalizing here so you see the rule). \r
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