document.write( "Question 789653: Can someone help me solve this?
\n" ); document.write( "Solve the system by the elimination method.
\n" ); document.write( "8x-5y=32
\n" ); document.write( "4x+5y=4
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Algebra.Com's Answer #478897 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Solve the system by the elimination method.\r
\n" ); document.write( "\n" ); document.write( "\"8x-5y=32\"....eq.1
\n" ); document.write( "\"4x%2B5y=4\".....eq.2
\n" ); document.write( "__________________.........as you can see from eq.1 and eq.2 you have \"-5y\" and \"5y\"; if you add them, you will get \"0\", so you can add both eq. and eliminate \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"8x-5y%2B4x%2B5y=32%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"12x-cross%285y%29+%2Bcross%285y%29=36\"\r
\n" ); document.write( "\n" ); document.write( "\"12x+=36\"\r
\n" ); document.write( "\n" ); document.write( "\"+x+=36%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"+highlight%28x+=3%29\"....plug it in eq.1 or eq.2 and find \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%2B5y=4\".....eq.2\r
\n" ); document.write( "\n" ); document.write( "\"4%2A3%2B5y=4\" \r
\n" ); document.write( "\n" ); document.write( "\"12%2B5y=4\" \r
\n" ); document.write( "\n" ); document.write( "\"+5y=4-12\"
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\n" ); document.write( "\"+5y=-8\" \r
\n" ); document.write( "\n" ); document.write( "\"+y=-8%2F5\" \r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=-1.6%29\"\r
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