document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67293>Question 67293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation in slope intercept form, y = mx + b, of the line that has a slope of –2/3, and contains the point, (6, –5).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47885 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47885\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=-2/3X+b<BR>\n" );
document.write( "NOW SUBSTITUTE THE X & Y VALUES OF THE POINT THUS & SOLVE FOR THE Y INTERCEPT(b)<BR>\n" );
document.write( "-5=-2/3*6+b<BR>\n" );
document.write( "-5=-4+b<BR>\n" );
document.write( "b=-5+4<BR>\n" );
document.write( "b=-1<BR>\n" );
document.write( "THUS THE EQUATION IS <BR>\n" );
document.write( "Y=-2/3X-1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );