document.write( "Question 67296This question is from textbook An Incremental Development
\n" ); document.write( ": There were 36 nickels, dimes and quarters whose value was $6. If there were three times as many quarters as nickels, how many coins of each kind were there?
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Algebra.Com's Answer #47883 by checkley71(8403)\"\" \"About 
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N+D+3N=36
\n" ); document.write( "5N+10D+25*3N=600
\n" ); document.write( "4N+D=36
\n" ); document.write( "4N=36-D
\n" ); document.write( "N=9-D/4
\n" ); document.write( "THUS
\n" ); document.write( "5(9-D/4)+10D+25*3(9-D/4)=600
\n" ); document.write( "45-5D/4+10D+75(9-D/4)=600
\n" ); document.write( "45-5D/4+10D+675-75D/4=600
\n" ); document.write( "10D-80D/4=600-45-675
\n" ); document.write( "(40D-80D)/4=-120
\n" ); document.write( "-40D/4=-120
\n" ); document.write( "-40D=-480
\n" ); document.write( "D=-480/-40
\n" ); document.write( "D=12 NUMBER OF DIMES
\n" ); document.write( "N+12=3N=36
\n" ); document.write( "4N=36-12
\n" ); document.write( "4N=24
\n" ); document.write( "N=24/4
\n" ); document.write( "N=6 NUMBER OF NICKELS
\n" ); document.write( "THUS 3N=18 THE NUMBER OF QUARTERS
\n" ); document.write( "PROOF
\n" ); document.write( "12*10+6*5+18*25=600
\n" ); document.write( "120+30+450=600
\n" ); document.write( "600=600
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