document.write( "Question 789263: The total age of three children is 40. The age of the oldest is twice the age of the youngest. The ages of the two older children differ by 5 years. What is the age of the youngest child? \n" ); document.write( "
Algebra.Com's Answer #478795 by stanbon(75887)\"\" \"About 
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The total age of three children is 40. The age of the oldest is twice the age of the youngest. The ages of the two older children differ by 5 years. What is the age of the youngest child?
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\n" ); document.write( "Equations:
\n" ); document.write( "e + m + y = 40
\n" ); document.write( "e = 2y
\n" ); document.write( "e - m = 5
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\n" ); document.write( "Substitute for \"y\" and for \"m\" and solve for \"e\":
\n" ); document.write( "e + (e-5) + (e/2) = 40
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\n" ); document.write( "2e - 5 + e/2 = 40
\n" ); document.write( "4e - 10 + e = 80
\n" ); document.write( "5e = 90
\n" ); document.write( "e = 18 (age of the eldest)
\n" ); document.write( "m = e-5 = 13 (age of the middle child)
\n" ); document.write( "y = e/2 = 9 (age of the youngest)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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