document.write( "Question 67297This question is from textbook An Increamental Development
\n" );
document.write( ": Find three consecutive multiples of 5 such that the sum of the square of the first two is 125 greater than the square of the third. \n" );
document.write( "
Algebra.Com's Answer #47878 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! x^2+(x+5)^2=(x+10)+125 \n" ); document.write( "x^2+x^2+10x+25=x+135 \n" ); document.write( "2x^2+10x-x+10-135=0 \n" ); document.write( "2x^2+9x-125=0 using the quadratic equation x=(-b+-sqrt[b^2-4ac])/2a we get \n" ); document.write( "x=(-9+-sqrt[81-4*2*-125])/2*2 \n" ); document.write( "x=(-9+-sqrt[81+000])/4 \n" ); document.write( "x=(-9+-sqrt1081)/4 \n" ); document.write( "x=(-9+-32.87856)/4 \n" ); document.write( "x=(-9+32.87856)/4 \n" ); document.write( "x=23.878564/4 \n" ); document.write( "x=5.96964 solution \n" ); document.write( "x=(-9-32.87856)/4 \n" ); document.write( "x=-41.87856/4 \n" ); document.write( "x=-10.46964 solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |