document.write( "Question 67297This question is from textbook An Increamental Development
\n" ); document.write( ": Find three consecutive multiples of 5 such that the sum of the square of the first two is 125 greater than the square of the third. \n" ); document.write( "
Algebra.Com's Answer #47878 by checkley71(8403)\"\" \"About 
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x^2+(x+5)^2=(x+10)+125
\n" ); document.write( "x^2+x^2+10x+25=x+135
\n" ); document.write( "2x^2+10x-x+10-135=0
\n" ); document.write( "2x^2+9x-125=0 using the quadratic equation x=(-b+-sqrt[b^2-4ac])/2a we get
\n" ); document.write( "x=(-9+-sqrt[81-4*2*-125])/2*2
\n" ); document.write( "x=(-9+-sqrt[81+000])/4
\n" ); document.write( "x=(-9+-sqrt1081)/4
\n" ); document.write( "x=(-9+-32.87856)/4
\n" ); document.write( "x=(-9+32.87856)/4
\n" ); document.write( "x=23.878564/4
\n" ); document.write( "x=5.96964 solution
\n" ); document.write( "x=(-9-32.87856)/4
\n" ); document.write( "x=-41.87856/4
\n" ); document.write( "x=-10.46964 solution\r
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