document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=789009>Question 789009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 38 men working 6hr a day can do a piece of work in 12days,find in what time 57 men working 8hr a day can do a piece of work twice as great able ,supposing 2 men of the first set to do as much work in 1hr as 3men of the 2nd set can do in 1.5 hrs ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478756 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  if 38 men working 6hr a day can do a piece of work in 12days,<BR>\n" );
document.write( "Find the number man-hrs required to do the job<BR>\n" );
document.write( "38*6*12 = 2736 man-hrs to complete the job<BR>\n" );
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document.write( "Find in what time 57 men working 8hr a day can do a piece of work twice as great<BR>\n" );
document.write( " A job twice as great would require: 2*2736 = 5472 man-hrs<BR>\n" );
document.write( "Let d = no. of days required for 57 men to do twice as much work<BR>\n" );
document.write( "57*8*d = 5472<BR>\n" );
document.write( "456d = 5472<BR>\n" );
document.write( "d = 5472/456<BR>\n" );
document.write( "d = 12 days<BR>\n" );
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document.write( "Supposing 2 men of the first set to do as much work in 1hr as 3men of the 2nd set can do in 1.5 hrs ?<BR>\n" );
document.write( "Not sure what you mean here </SPAN>\n" );
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