document.write( "Question 789099: 1.) Find the solutions of the equation.
\n" ); document.write( " I already subuted u for x^(2/3) then i got a quadratic equation 3u^2 + 5u - 2=0 and i got u = 1/3 and -2 and i have to sub something back but I do not know what to do now after i got those two answers for u?\r
\n" ); document.write( "\n" ); document.write( "3x^(4/3) + 5x^(2/3) - 2=0 \r
\n" ); document.write( "\n" ); document.write( "Can someone please help me on this problem and go step by step with this equtaion for me? THANK YOU!
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Algebra.Com's Answer #478721 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You let \"u+=+x%5E%282%2F3%29%5E%22%22\"\r
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\n" ); document.write( "\n" ); document.write( "So because the first solution for 'u' is \"u+=+1%2F3\", this means...\r
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\n" ); document.write( "\n" ); document.write( "\"u+=+1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E%282%2F3%29%5E%22%22+=+1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E%282%2F3%29%5E%22%22%29%5E3+=+%281%2F3%29%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+1%2F27\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%22%22%2B-sqrt%281%2F27%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%281%2F27%29\" or \"x+=+-sqrt%281%2F27%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%281%29%2Fsqrt%2827%29\" or \"x+=+-sqrt%281%29%2Fsqrt%2827%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1%2Fsqrt%2827%29\" or \"x+=+-1%2Fsqrt%2827%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1%2Fsqrt%289%2A3%29\" or \"x+=+-1%2Fsqrt%289%2A3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1%2F%28sqrt%289%29%2Asqrt%283%29%29\" or \"x+=+-1%2F%28sqrt%289%29%2Asqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1%2F%283%2Asqrt%283%29%29\" or \"x+=+-1%2F%283%2Asqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281%2Asqrt%283%29%29%2F%283%2Asqrt%283%29%2Asqrt%283%29%29\" or \"x+=+-%281%2Asqrt%283%29%29%2F%283%2Asqrt%283%29%2Asqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28sqrt%283%29%29%2F%283%2A3%29\" or \"x+=+-%28sqrt%283%29%29%2F%283%2A3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28sqrt%283%29%29%2F%289%29\" or \"x+=+-%28sqrt%283%29%29%2F%289%29\"\r
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\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "Now if \"u+=+-2\", then...\r
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\n" ); document.write( "\n" ); document.write( "\"u+=+-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E%282%2F3%29%5E%22%22+=+-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E%282%2F3%29%5E%22%22%29%5E3+=+%28-2%29%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+-8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%22%22%2B-sqrt%28-8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%28-8%29\" or \"x+=+-sqrt%28-8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%28-1%2A4%2A2%29\" or \"x+=+-sqrt%28-1%2A4%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%28-1%29%2Asqrt%284%29%2Asqrt%282%29\" or \"x+=+-sqrt%28-1%29%2Asqrt%284%29%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+i%2A2%2Asqrt%282%29\" or \"x+=+-i%2A2%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+2i%2Asqrt%282%29\" or \"x+=+-2i%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since these solutions are complex and not real, we can ignore them.\r
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\n" ); document.write( "\n" ); document.write( "So the two *possible* real numbered solutions are\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28sqrt%283%29%29%2F%289%29\" or \"x+=+-%28sqrt%283%29%29%2F%289%29\"\r
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\n" ); document.write( "\n" ); document.write( "It turns out that when you plug each back into the original equation, only \"x+=+%28sqrt%283%29%29%2F%289%29\" works while \"x+=+-%28sqrt%283%29%29%2F%289%29\" makes the original equation false.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the only solution is \"x+=+%28sqrt%283%29%29%2F%289%29\"
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